(6x^2-3x^3-27x)/(9x^2)

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Solution for (6x^2-3x^3-27x)/(9x^2) equation: 


D( x )

9*x^2 = 0

9*x^2 = 0

9*x^2 = 0

9*x^2 = 0 // : 9

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

(6*x^2-(3*x^3)-(27*x))/(9*x^2) = 0

(6*x^2-3*x^3-27*x)/(9*x^2) = 0

6*x^2-3*x^3-27*x = 0

3*x*(2*x-x^2-9) = 0

2*x-x^2-9 = 0

DELTA = 2^2-(-9*(-1)*4)

DELTA = -32

DELTA < 0

3*x = 0

(3*x)/(9*x^2) = 0

3*x = 0 // : 3

x = 0

x in { 0} 

x belongs to the empty set

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